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411230231444323 is a prime number
BaseRepresentation
bin101110110000000101111111…
…1110111011011101101100011
31222221001020002212222222020201
41131200023333313123231203
5412400044003222204243
64014340321005250031
7152422255331121424
oct13540137767335543
91887036085888221
10411230231444323
1110a03784199a335
123a157210563917
131485cac929c865
147379913d5564b
153282096d5204d
hex17602ffddbb63

411230231444323 has 2 divisors, whose sum is σ = 411230231444324. Its totient is φ = 411230231444322.

The previous prime is 411230231444309. The next prime is 411230231444399. The reversal of 411230231444323 is 323444132032114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 411230231444323 - 225 = 411230197889891 is a prime.

It is a super-2 number, since 2×4112302314443232 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (411230231444023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205615115722161 + 205615115722162.

It is an arithmetic number, because the mean of its divisors is an integer number (205615115722162).

Almost surely, 2411230231444323 is an apocalyptic number.

411230231444323 is a deficient number, since it is larger than the sum of its proper divisors (1).

411230231444323 is an equidigital number, since it uses as much as digits as its factorization.

411230231444323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 165888, while the sum is 37.

Adding to 411230231444323 its reverse (323444132032114), we get a palindrome (734674363476437).

The spelling of 411230231444323 in words is "four hundred eleven trillion, two hundred thirty billion, two hundred thirty-one million, four hundred forty-four thousand, three hundred twenty-three".