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4112444029963 is a prime number
BaseRepresentation
bin111011110110000000110…
…000111111110000001011
3112120010221021222021010111
4323312000300333300023
51014334241132424323
612425121455455151
7603054124331263
oct73660060776013
915503837867114
104112444029963
111346094497655
125650292274b7
1323aa567591c9
14103086d647a3
1571e92924c0d
hex3bd80c3fc0b

4112444029963 has 2 divisors, whose sum is σ = 4112444029964. Its totient is φ = 4112444029962.

The previous prime is 4112444029957. The next prime is 4112444029973. The reversal of 4112444029963 is 3699204442114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4112444029963 - 221 = 4112441932811 is a prime.

It is not a weakly prime, because it can be changed into another prime (4112444029973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056222014981 + 2056222014982.

It is an arithmetic number, because the mean of its divisors is an integer number (2056222014982).

Almost surely, 24112444029963 is an apocalyptic number.

4112444029963 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112444029963 is an equidigital number, since it uses as much as digits as its factorization.

4112444029963 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1492992, while the sum is 49.

The spelling of 4112444029963 in words is "four trillion, one hundred twelve billion, four hundred forty-four million, twenty-nine thousand, nine hundred sixty-three".