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4112965481 is a prime number
BaseRepresentation
bin1111010100100110…
…1101111101101001
3101121122021021221212
43311021231331221
531410404343411
61520043042505
7203631426002
oct36511557551
911548237855
104112965481
111820730929
12969510435
135071547b1
142b035c1a9
1519113b68b
hexf526df69

4112965481 has 2 divisors, whose sum is σ = 4112965482. Its totient is φ = 4112965480.

The previous prime is 4112965477. The next prime is 4112965537. The reversal of 4112965481 is 1845692114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3487965481 + 625000000 = 59059^2 + 25000^2 .

It is a cyclic number.

It is not a de Polignac number, because 4112965481 - 22 = 4112965477 is a prime.

It is a super-2 number, since 2×41129654812 = 33832970095795122722, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4112965411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056482740 + 2056482741.

It is an arithmetic number, because the mean of its divisors is an integer number (2056482741).

Almost surely, 24112965481 is an apocalyptic number.

It is an amenable number.

4112965481 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112965481 is an equidigital number, since it uses as much as digits as its factorization.

4112965481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 69120, while the sum is 41.

The square root of 4112965481 is about 64132.4058569457. The cubic root of 4112965481 is about 1602.2060040736.

The spelling of 4112965481 in words is "four billion, one hundred twelve million, nine hundred sixty-five thousand, four hundred eighty-one".