4113000222231 has 24 divisors (see below), whose sum is σ = 5967651315024. Its totient is φ = 2517761950720.

The previous prime is 4113000222223. The next prime is 4113000222239. The reversal of 4113000222231 is 1322220003114.

It is an interprime number because it is at equal distance from previous prime (4113000222223) and next prime (4113000222239).

It is not a de Polignac number, because 4113000222231 - 2³ = 4113000222223 is a prime.

It is a super-2 number, since 2×4113000222231² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4113000222198 and 4113000222207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4113000222239) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 57817440 + ... + 57888533.

It is an arithmetic number, because the mean of its divisors is an integer number (248652138126).

Almost surely, 2^{4113000222231} is an apocalyptic number.

4113000222231 is a gapful number since it is divisible by the number (41) formed by its first and last digit.

4113000222231 is a deficient number, since it is larger than the sum of its proper divisors (1854651092793).

4113000222231 is a wasteful number, since it uses less digits than its factorization.

4113000222231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 115706051 (or 115706034 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 4113000222231 its reverse (1322220003114), we get a palindrome (5435220225345).

The spelling of 4113000222231 in words is "four trillion, one hundred thirteen billion, two hundred twenty-two thousand, two hundred thirty-one".