Base | Representation |
---|---|
bin | 1111010100100111… |
… | …0111001011101001 |
3 | 101121122100012202101 |
4 | 3311021313023221 |
5 | 31410412100431 |
6 | 1520043533401 |
7 | 203631644044 |
oct | 36511671351 |
9 | 11548305671 |
10 | 4113003241 |
11 | 1820757236 |
12 | 96952a261 |
13 | 507168a39 |
14 | 2b036bc5b |
15 | 191147961 |
hex | f52772e9 |
4113003241 has 2 divisors, whose sum is σ = 4113003242. Its totient is φ = 4113003240.
The previous prime is 4113003211. The next prime is 4113003247. The reversal of 4113003241 is 1423003114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2439866025 + 1673137216 = 49395^2 + 40904^2 .
It is a cyclic number.
It is not a de Polignac number, because 4113003241 - 213 = 4112995049 is a prime.
It is not a weakly prime, because it can be changed into another prime (4113003247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056501620 + 2056501621.
It is an arithmetic number, because the mean of its divisors is an integer number (2056501621).
Almost surely, 24113003241 is an apocalyptic number.
It is an amenable number.
4113003241 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113003241 is an equidigital number, since it uses as much as digits as its factorization.
4113003241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 19.
The square root of 4113003241 is about 64132.7002472218. The cubic root of 4113003241 is about 1602.2109071956.
Adding to 4113003241 its reverse (1423003114), we get a palindrome (5536006355).
The spelling of 4113003241 in words is "four billion, one hundred thirteen million, three thousand, two hundred forty-one".
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