Base | Representation |
---|---|
bin | 10010101101000010111110… |
… | …10110111000100001111011 |
3 | 12101122000020211011010122111 |
4 | 21112201133112320201323 |
5 | 20342334130401120411 |
6 | 223250542303233151 |
7 | 11443362602125366 |
oct | 1126413726704173 |
9 | 171560224133574 |
10 | 41130206660731 |
11 | 1211824a441391 |
12 | 4743386ba87b7 |
13 | 19c473c4b4a86 |
14 | a229d96250dd |
15 | 4b4d57519721 |
hex | 25685f5b887b |
41130206660731 has 2 divisors, whose sum is σ = 41130206660732. Its totient is φ = 41130206660730.
The previous prime is 41130206660623. The next prime is 41130206660747. The reversal of 41130206660731 is 13706660203114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41130206660731 - 27 = 41130206660603 is a prime.
It is a super-2 number, since 2×411302066607312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (41130206660531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20565103330365 + 20565103330366.
It is an arithmetic number, because the mean of its divisors is an integer number (20565103330366).
Almost surely, 241130206660731 is an apocalyptic number.
41130206660731 is a deficient number, since it is larger than the sum of its proper divisors (1).
41130206660731 is an equidigital number, since it uses as much as digits as its factorization.
41130206660731 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108864, while the sum is 40.
Adding to 41130206660731 its reverse (13706660203114), we get a palindrome (54836866863845).
The spelling of 41130206660731 in words is "forty-one trillion, one hundred thirty billion, two hundred six million, six hundred sixty thousand, seven hundred thirty-one".
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