41130221340031 has 8 divisors (see below), whose sum is σ = 41261665245120. Its totient is φ = 40998882720768.

The previous prime is 41130221339993. The next prime is 41130221340067. The reversal of 41130221340031 is 13004312203114.

41130221340031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 41130221340031 - 2⁷ = 41130221339903 is a prime.

It is a super-2 number, since 2×41130221340031² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41130221339978 and 41130221340005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41130221340331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25538866 + ... + 27101551.

It is an arithmetic number, because the mean of its divisors is an integer number (5157708155640).

Almost surely, 2^{41130221340031} is an apocalyptic number.

41130221340031 is a deficient number, since it is larger than the sum of its proper divisors (131443905089).

41130221340031 is a wasteful number, since it uses less digits than its factorization.

41130221340031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52642913.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 41130221340031 its reverse (13004312203114), we get a palindrome (54134533543145).

The spelling of 41130221340031 in words is "forty-one trillion, one hundred thirty billion, two hundred twenty-one million, three hundred forty thousand, thirty-one".