Base | Representation |
---|---|
bin | 111011110110100100010… |
… | …010110101001100100001 |
3 | 112120012110211120212111011 |
4 | 323312210102311030201 |
5 | 1014342001231232202 |
6 | 12425300551420521 |
7 | 603104653011166 |
oct | 73664422651441 |
9 | 15505424525434 |
10 | 4113040102177 |
11 | 134636aa02516 |
12 | 565174984741 |
13 | 23ab200ab066 |
14 | 1031021a806d |
15 | 71ec9e18bd7 |
hex | 3bda44b5321 |
4113040102177 has 2 divisors, whose sum is σ = 4113040102178. Its totient is φ = 4113040102176.
The previous prime is 4113040102159. The next prime is 4113040102253. The reversal of 4113040102177 is 7712010403114.
4113040102177 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2625618381376 + 1487421720801 = 1620376^2 + 1219599^2 .
It is a cyclic number.
It is not a de Polignac number, because 4113040102177 - 211 = 4113040100129 is a prime.
It is not a weakly prime, because it can be changed into another prime (4113040102117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056520051088 + 2056520051089.
It is an arithmetic number, because the mean of its divisors is an integer number (2056520051089).
Almost surely, 24113040102177 is an apocalyptic number.
It is an amenable number.
4113040102177 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113040102177 is an equidigital number, since it uses as much as digits as its factorization.
4113040102177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4704, while the sum is 31.
The spelling of 4113040102177 in words is "four trillion, one hundred thirteen billion, forty million, one hundred two thousand, one hundred seventy-seven".
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