Base | Representation |
---|---|
bin | 100110010011100101… |
… | …010111011001000001 |
3 | 10221011110202200000122 |
4 | 212103211113121001 |
5 | 1133213433022203 |
6 | 30521210430025 |
7 | 2654154422363 |
oct | 462345273101 |
9 | 127143680018 |
10 | 41130751553 |
11 | 16497267461 |
12 | 7b7a732315 |
13 | 3b5640c318 |
14 | 1dc2832d33 |
15 | 110ade4538 |
hex | 993957641 |
41130751553 has 2 divisors, whose sum is σ = 41130751554. Its totient is φ = 41130751552.
The previous prime is 41130751477. The next prime is 41130751567. The reversal of 41130751553 is 35515703114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27797892529 + 13332859024 = 166727^2 + 115468^2 .
It is a cyclic number.
It is not a de Polignac number, because 41130751553 - 212 = 41130747457 is a prime.
It is a super-2 number, since 2×411307515532 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (41130751573) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20565375776 + 20565375777.
It is an arithmetic number, because the mean of its divisors is an integer number (20565375777).
Almost surely, 241130751553 is an apocalyptic number.
It is an amenable number.
41130751553 is a deficient number, since it is larger than the sum of its proper divisors (1).
41130751553 is an equidigital number, since it uses as much as digits as its factorization.
41130751553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31500, while the sum is 35.
The spelling of 41130751553 in words is "forty-one billion, one hundred thirty million, seven hundred fifty-one thousand, five hundred fifty-three".
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