Base | Representation |
---|---|
bin | 111011110110100111111… |
… | …000000110100110000111 |
3 | 112120012122000200101021021 |
4 | 323312213320012212013 |
5 | 1014342112123020143 |
6 | 12425310535532011 |
7 | 603106312612330 |
oct | 73664770064607 |
9 | 15505560611237 |
10 | 4113100204423 |
11 | 13463a09231a1 |
12 | 565190b2a007 |
13 | 23ab2c692712 |
14 | 10310a171287 |
15 | 71ed033bced |
hex | 3bda7e06987 |
4113100204423 has 4 divisors (see below), whose sum is σ = 4700685947920. Its totient is φ = 3525514460928.
The previous prime is 4113100204403. The next prime is 4113100204463. The reversal of 4113100204423 is 3244020013114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4113100204423 - 25 = 4113100204391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113100204403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 293792871738 + ... + 293792871751.
It is an arithmetic number, because the mean of its divisors is an integer number (1175171486980).
Almost surely, 24113100204423 is an apocalyptic number.
4113100204423 is a deficient number, since it is larger than the sum of its proper divisors (587585743497).
4113100204423 is an equidigital number, since it uses as much as digits as its factorization.
4113100204423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 587585743496.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4113100204423 its reverse (3244020013114), we get a palindrome (7357120217537).
The spelling of 4113100204423 in words is "four trillion, one hundred thirteen billion, one hundred million, two hundred four thousand, four hundred twenty-three".
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