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4113100204423 = 7587585743489
BaseRepresentation
bin111011110110100111111…
…000000110100110000111
3112120012122000200101021021
4323312213320012212013
51014342112123020143
612425310535532011
7603106312612330
oct73664770064607
915505560611237
104113100204423
1113463a09231a1
12565190b2a007
1323ab2c692712
1410310a171287
1571ed033bced
hex3bda7e06987

4113100204423 has 4 divisors (see below), whose sum is σ = 4700685947920. Its totient is φ = 3525514460928.

The previous prime is 4113100204403. The next prime is 4113100204463. The reversal of 4113100204423 is 3244020013114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4113100204423 - 25 = 4113100204391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4113100204403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 293792871738 + ... + 293792871751.

It is an arithmetic number, because the mean of its divisors is an integer number (1175171486980).

Almost surely, 24113100204423 is an apocalyptic number.

4113100204423 is a deficient number, since it is larger than the sum of its proper divisors (587585743497).

4113100204423 is an equidigital number, since it uses as much as digits as its factorization.

4113100204423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 587585743496.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 4113100204423 its reverse (3244020013114), we get a palindrome (7357120217537).

The spelling of 4113100204423 in words is "four trillion, one hundred thirteen billion, one hundred million, two hundred four thousand, four hundred twenty-three".

Divisors: 1 7 587585743489 4113100204423