Base | Representation |
---|---|
bin | 1111010100101001… |
… | …0100001011010011 |
3 | 101121122120020122222 |
4 | 3311022110023103 |
5 | 31410424401003 |
6 | 1520050251255 |
7 | 203632650224 |
oct | 36512241323 |
9 | 11548506588 |
10 | 4113122003 |
11 | 1820828491 |
12 | 969586b2b |
13 | 5071aab03 |
14 | 2b039d24b |
15 | 19116cc38 |
hex | f52942d3 |
4113122003 has 2 divisors, whose sum is σ = 4113122004. Its totient is φ = 4113122002.
The previous prime is 4113121981. The next prime is 4113122017. The reversal of 4113122003 is 3002213114.
4113122003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4113122003 - 218 = 4112859859 is a prime.
It is a super-2 number, since 2×41131220032 = 33835545223125464018, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4113122023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056561001 + 2056561002.
It is an arithmetic number, because the mean of its divisors is an integer number (2056561002).
Almost surely, 24113122003 is an apocalyptic number.
4113122003 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113122003 is an equidigital number, since it uses as much as digits as its factorization.
4113122003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 4113122003 is about 64133.6261488464. The cubic root of 4113122003 is about 1602.2263282013.
Adding to 4113122003 its reverse (3002213114), we get a palindrome (7115335117).
The spelling of 4113122003 in words is "four billion, one hundred thirteen million, one hundred twenty-two thousand, three".
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