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411313210241 is a prime number
BaseRepresentation
bin1011111110001000010…
…11011000001110000001
31110022200010100222220112
411333010023120032001
523214332140211431
6512542113321105
741500503413153
oct5770413301601
91408603328815
10411313210241
1114948964772a
126786bb66195
132ca2c40a59b
1415c9c8c4ad3
15aa74c05c2b
hex5fc42d8381

411313210241 has 2 divisors, whose sum is σ = 411313210242. Its totient is φ = 411313210240.

The previous prime is 411313210207. The next prime is 411313210247. The reversal of 411313210241 is 142012313114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 336289809025 + 75023401216 = 579905^2 + 273904^2 .

It is a cyclic number.

It is not a de Polignac number, because 411313210241 - 214 = 411313193857 is a prime.

It is not a weakly prime, because it can be changed into another prime (411313210247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205656605120 + 205656605121.

It is an arithmetic number, because the mean of its divisors is an integer number (205656605121).

Almost surely, 2411313210241 is an apocalyptic number.

It is an amenable number.

411313210241 is a deficient number, since it is larger than the sum of its proper divisors (1).

411313210241 is an equidigital number, since it uses as much as digits as its factorization.

411313210241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 411313210241 its reverse (142012313114), we get a palindrome (553325523355).

The spelling of 411313210241 in words is "four hundred eleven billion, three hundred thirteen million, two hundred ten thousand, two hundred forty-one".