Base | Representation |
---|---|
bin | 111011110110101001111… |
… | …001110111100000011111 |
3 | 112120012201101200121201012 |
4 | 323312221321313200133 |
5 | 1014342144330040333 |
6 | 12425314153005435 |
7 | 603110205011120 |
oct | 73665171674037 |
9 | 15505641617635 |
10 | 4113134221343 |
11 | 1346409047654 |
12 | 5651a03b387b |
13 | 23ab36742b84 |
14 | 1031108a8047 |
15 | 71ed330ae48 |
hex | 3bda9e7781f |
4113134221343 has 4 divisors (see below), whose sum is σ = 4700724824400. Its totient is φ = 3525543618288.
The previous prime is 4113134221327. The next prime is 4113134221409. The reversal of 4113134221343 is 3431224313114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4113134221343 - 24 = 4113134221327 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113134221303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 293795301518 + ... + 293795301531.
It is an arithmetic number, because the mean of its divisors is an integer number (1175181206100).
Almost surely, 24113134221343 is an apocalyptic number.
4113134221343 is a deficient number, since it is larger than the sum of its proper divisors (587590603057).
4113134221343 is an equidigital number, since it uses as much as digits as its factorization.
4113134221343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 587590603056.
The product of its digits is 20736, while the sum is 32.
Adding to 4113134221343 its reverse (3431224313114), we get a palindrome (7544358534457).
The spelling of 4113134221343 in words is "four trillion, one hundred thirteen billion, one hundred thirty-four million, two hundred twenty-one thousand, three hundred forty-three".
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