Base | Representation |
---|---|
bin | 111011110110101111110… |
… | …111011000010000000001 |
3 | 112120012222100212200222111 |
4 | 323312233313120100001 |
5 | 1014342400430413241 |
6 | 12425332124335321 |
7 | 603112531050244 |
oct | 73665767302001 |
9 | 15505870780874 |
10 | 4113234232321 |
11 | 134645a546355 |
12 | 5652099a4541 |
13 | 23ab5138b676 |
14 | 10311dc9d25b |
15 | 71edbeb3c81 |
hex | 3bdafdd8401 |
4113234232321 has 2 divisors, whose sum is σ = 4113234232322. Its totient is φ = 4113234232320.
The previous prime is 4113234232291. The next prime is 4113234232337. The reversal of 4113234232321 is 1232324323114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3611919255025 + 501314977296 = 1900505^2 + 708036^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4113234232321 is a prime.
It is not a weakly prime, because it can be changed into another prime (4113234232721) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056617116160 + 2056617116161.
It is an arithmetic number, because the mean of its divisors is an integer number (2056617116161).
Almost surely, 24113234232321 is an apocalyptic number.
It is an amenable number.
4113234232321 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113234232321 is an equidigital number, since it uses as much as digits as its factorization.
4113234232321 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20736, while the sum is 31.
Adding to 4113234232321 its reverse (1232324323114), we get a palindrome (5345558555435).
The spelling of 4113234232321 in words is "four trillion, one hundred thirteen billion, two hundred thirty-four million, two hundred thirty-two thousand, three hundred twenty-one".
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