Base | Representation |
---|---|
bin | 111011110110110000111… |
… | …100000000100100010111 |
3 | 112120020000121201201220101 |
4 | 323312300330000210113 |
5 | 1014342420032121010 |
6 | 12425334010114531 |
7 | 603113140011040 |
oct | 73666074004427 |
9 | 15506017651811 |
10 | 4113252223255 |
11 | 134646971419a |
12 | 565213a1ba47 |
13 | 23ab5501a4a6 |
14 | 1031224238c7 |
15 | 71edd86973a |
hex | 3bdb0f00917 |
4113252223255 has 32 divisors (see below), whose sum is σ = 5969199495168. Its totient is φ = 2659886275200.
The previous prime is 4113252223229. The next prime is 4113252223271. The reversal of 4113252223255 is 5523222523114.
4113252223255 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4113252223255 - 27 = 4113252223127 is a prime.
It is a super-2 number, since 2×41132522232552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 35926156 + ... + 36040465.
It is an arithmetic number, because the mean of its divisors is an integer number (186537484224).
Almost surely, 24113252223255 is an apocalyptic number.
4113252223255 is a deficient number, since it is larger than the sum of its proper divisors (1855947271913).
4113252223255 is a wasteful number, since it uses less digits than its factorization.
4113252223255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71966727.
The product of its digits is 144000, while the sum is 37.
Adding to 4113252223255 its reverse (5523222523114), we get a palindrome (9636474746369).
The spelling of 4113252223255 in words is "four trillion, one hundred thirteen billion, two hundred fifty-two million, two hundred twenty-three thousand, two hundred fifty-five".
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