Base | Representation |
---|---|
bin | 111011110110110011111… |
… | …011100101001111110111 |
3 | 112120020011010020011102220 |
4 | 323312303323211033313 |
5 | 1014343020411133444 |
6 | 12425343002333423 |
7 | 603114316612221 |
oct | 73666373451767 |
9 | 15506133204386 |
10 | 4113302442999 |
11 | 1346494aa5012 |
12 | 5652287ba273 |
13 | 23ab62551909 |
14 | 103128d77411 |
15 | 71ee2e89619 |
hex | 3bdb3ee53f7 |
4113302442999 has 4 divisors (see below), whose sum is σ = 5484403257336. Its totient is φ = 2742201628664.
The previous prime is 4113302442983. The next prime is 4113302443027. The reversal of 4113302442999 is 9992442033114.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4113302442999 - 24 = 4113302442983 is a prime.
It is a super-2 number, since 2×41133024429992 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113302442919) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 685550407164 + ... + 685550407169.
It is an arithmetic number, because the mean of its divisors is an integer number (1371100814334).
Almost surely, 24113302442999 is an apocalyptic number.
4113302442999 is a deficient number, since it is larger than the sum of its proper divisors (1371100814337).
4113302442999 is a wasteful number, since it uses less digits than its factorization.
4113302442999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1371100814336.
The product of its (nonzero) digits is 1679616, while the sum is 51.
The spelling of 4113302442999 in words is "four trillion, one hundred thirteen billion, three hundred two million, four hundred forty-two thousand, nine hundred ninety-nine".
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