Base | Representation |
---|---|
bin | 111011110110110011111… |
… | …110111000111100111101 |
3 | 112120020011011212012221021 |
4 | 323312303332320330331 |
5 | 1014343021121411031 |
6 | 12425343033104141 |
7 | 603114330153304 |
oct | 73666376707475 |
9 | 15506134765837 |
10 | 4113303310141 |
11 | 1346495537563 |
12 | 565228b58051 |
13 | 23ab6279650c |
14 | 10312912143b |
15 | 71ee30ab511 |
hex | 3bdb3fb8f3d |
4113303310141 has 8 divisors (see below), whose sum is σ = 4118829437664. Its totient is φ = 4107778518480.
The previous prime is 4113303310117. The next prime is 4113303310201. The reversal of 4113303310141 is 1410133033114.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4113303310141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113303311141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5906626 + ... + 6566188.
It is an arithmetic number, because the mean of its divisors is an integer number (514853679708).
Almost surely, 24113303310141 is an apocalyptic number.
It is an amenable number.
4113303310141 is a deficient number, since it is larger than the sum of its proper divisors (5526127523).
4113303310141 is an equidigital number, since it uses as much as digits as its factorization.
4113303310141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 667931.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 4113303310141 its reverse (1410133033114), we get a palindrome (5523436343255).
The spelling of 4113303310141 in words is "four trillion, one hundred thirteen billion, three hundred three million, three hundred ten thousand, one hundred forty-one".
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