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4113312169 is a prime number
BaseRepresentation
bin1111010100101100…
…0010100110101001
3101121122220220112011
43311023002212221
531411001442134
61520054315521
7203634401521
oct36513024651
911548826464
104113312169
11182094834a
12969658ba1
13507246535
142b040c681
151911a9264
hexf52c29a9

4113312169 has 2 divisors, whose sum is σ = 4113312170. Its totient is φ = 4113312168.

The previous prime is 4113312143. The next prime is 4113312211. The reversal of 4113312169 is 9612133114.

4113312169 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3969000000 + 144312169 = 63000^2 + 12013^2 .

It is a cyclic number.

It is not a de Polignac number, because 4113312169 - 211 = 4113310121 is a prime.

It is a super-2 number, since 2×41133121692 = 33838673999286969122, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4113312169.

It is not a weakly prime, because it can be changed into another prime (4113315169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056656084 + 2056656085.

It is an arithmetic number, because the mean of its divisors is an integer number (2056656085).

Almost surely, 24113312169 is an apocalyptic number.

It is an amenable number.

4113312169 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113312169 is an equidigital number, since it uses as much as digits as its factorization.

4113312169 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3888, while the sum is 31.

The square root of 4113312169 is about 64135.1087081015. The cubic root of 4113312169 is about 1602.2510202541.

The spelling of 4113312169 in words is "four billion, one hundred thirteen million, three hundred twelve thousand, one hundred sixty-nine".