Base | Representation |
---|---|
bin | 111011110110110101001… |
… | …110010010100010010111 |
3 | 112120020012122000200121110 |
4 | 323312311032102202113 |
5 | 1014343041433434221 |
6 | 12425345055150103 |
7 | 603115002113103 |
oct | 73666516224227 |
9 | 15506178020543 |
10 | 4113324124311 |
11 | 13464a6263556 |
12 | 565233b15333 |
13 | 23ab66ba33ac |
14 | 10312bbbc903 |
15 | 71ee4d1d776 |
hex | 3bdb5392897 |
4113324124311 has 16 divisors (see below), whose sum is σ = 5506428479840. Its totient is φ = 2731239181440.
The previous prime is 4113324124309. The next prime is 4113324124313. The reversal of 4113324124311 is 1134214233114.
It is an interprime number because it is at equal distance from previous prime (4113324124309) and next prime (4113324124313).
It is not a de Polignac number, because 4113324124311 - 21 = 4113324124309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113324124313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1882216 + ... + 3430653.
It is an arithmetic number, because the mean of its divisors is an integer number (344151779990).
Almost surely, 24113324124311 is an apocalyptic number.
4113324124311 is a deficient number, since it is larger than the sum of its proper divisors (1393104355529).
4113324124311 is a wasteful number, since it uses less digits than its factorization.
4113324124311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5313906.
The product of its digits is 6912, while the sum is 30.
Adding to 4113324124311 its reverse (1134214233114), we get a palindrome (5247538357425).
The spelling of 4113324124311 in words is "four trillion, one hundred thirteen billion, three hundred twenty-four million, one hundred twenty-four thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •