41140132324483 has 2 divisors, whose sum is σ = 41140132324484. Its totient is φ = 41140132324482.

The previous prime is 41140132324477. The next prime is 41140132324519. The reversal of 41140132324483 is 38442323104114.

41140132324483 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41140132324483 is a prime.

It is not a weakly prime, because it can be changed into another prime (41140132324283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20570066162241 + 20570066162242.

It is an arithmetic number, because the mean of its divisors is an integer number (20570066162242).

Almost surely, 2^{41140132324483} is an apocalyptic number.

41140132324483 is a deficient number, since it is larger than the sum of its proper divisors (1).

41140132324483 is an equidigital number, since it uses as much as digits as its factorization.

41140132324483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 221184, while the sum is 40.

Adding to 41140132324483 its reverse (38442323104114), we get a palindrome (79582455428597).

The spelling of 41140132324483 in words is "forty-one trillion, one hundred forty billion, one hundred thirty-two million, three hundred twenty-four thousand, four hundred eighty-three".