411404033340233 has 2 divisors, whose sum is σ = 411404033340234. Its totient is φ = 411404033340232.

The previous prime is 411404033340197. The next prime is 411404033340239. The reversal of 411404033340233 is 332043330404114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 411387594766864 + 16438573369 = 20282692^2 + 128213^2 .

It is a cyclic number.

It is not a de Polignac number, because 411404033340233 - 2¹⁰ = 411404033339209 is a prime.

It is a super-2 number, since 2×411404033340233² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 411404033340193 and 411404033340202.

It is not a weakly prime, because it can be changed into another prime (411404033340239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205702016670116 + 205702016670117.

It is an arithmetic number, because the mean of its divisors is an integer number (205702016670117).

Almost surely, 2^{411404033340233} is an apocalyptic number.

It is an amenable number.

411404033340233 is a deficient number, since it is larger than the sum of its proper divisors (1).

411404033340233 is an equidigital number, since it uses as much as digits as its factorization.

411404033340233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 411404033340233 its reverse (332043330404114), we get a palindrome (743447363744347).

The spelling of 411404033340233 in words is "four hundred eleven trillion, four hundred four billion, thirty-three million, three hundred forty thousand, two hundred thirty-three".