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4114042234411 is a prime number
BaseRepresentation
bin111011110111100000000…
…001101010011000101011
3112120022001200021110110211
4323313200001222120223
51014401024303000121
612425544230521551
7603141542002414
oct73674001523053
915508050243424
104114042234411
11134683465227a
125653b45062b7
1323ac4c8b3905
1410319930c80b
1572037dbbce1
hex3bde006a62b

4114042234411 has 2 divisors, whose sum is σ = 4114042234412. Its totient is φ = 4114042234410.

The previous prime is 4114042234373. The next prime is 4114042234427. The reversal of 4114042234411 is 1144322404114.

4114042234411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4114042234411 is a prime.

It is not a weakly prime, because it can be changed into another prime (4114042234441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057021117205 + 2057021117206.

It is an arithmetic number, because the mean of its divisors is an integer number (2057021117206).

Almost surely, 24114042234411 is an apocalyptic number.

4114042234411 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114042234411 is an equidigital number, since it uses as much as digits as its factorization.

4114042234411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 4114042234411 its reverse (1144322404114), we get a palindrome (5258364638525).

The spelling of 4114042234411 in words is "four trillion, one hundred fourteen billion, forty-two million, two hundred thirty-four thousand, four hundred eleven".