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4114100343351 = 31371366781117
BaseRepresentation
bin111011110111100011011…
…111010101001000110111
3112120022012201121200221210
4323313203133111020313
51014401134141441401
612425554104212503
7603143145632265
oct73674337251067
915508181550853
104114100343351
111346864431399
1256540ba6a133
1323ac5b94abbb
141031a2d17435
157203d0494d6
hex3bde37d5237

4114100343351 has 4 divisors (see below), whose sum is σ = 5485467124472. Its totient is φ = 2742733562232.

The previous prime is 4114100343347. The next prime is 4114100343377. The reversal of 4114100343351 is 1533430014114.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 4114100343351 - 22 = 4114100343347 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4114100743351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 685683390556 + ... + 685683390561.

It is an arithmetic number, because the mean of its divisors is an integer number (1371366781118).

Almost surely, 24114100343351 is an apocalyptic number.

4114100343351 is a deficient number, since it is larger than the sum of its proper divisors (1371366781121).

4114100343351 is a wasteful number, since it uses less digits than its factorization.

4114100343351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1371366781120.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 4114100343351 its reverse (1533430014114), we get a palindrome (5647530357465).

The spelling of 4114100343351 in words is "four trillion, one hundred fourteen billion, one hundred million, three hundred forty-three thousand, three hundred fifty-one".

Divisors: 1 3 1371366781117 4114100343351