Base | Representation |
---|---|
bin | 1011111110010011111… |
… | …01000010011001010100 |
3 | 1110022220212201020001112 |
4 | 11333021331002121110 |
5 | 23220031442123012 |
6 | 512555454314152 |
7 | 41503061161613 |
oct | 5771175023124 |
9 | 1408825636045 |
10 | 411410114132 |
11 | 149529313a96 |
12 | 678984b8958 |
13 | 2ca46508a74 |
14 | 15cab70b87a |
15 | aa7d498122 |
hex | 5fc9f42654 |
411410114132 has 6 divisors (see below), whose sum is σ = 719967699738. Its totient is φ = 205705057064.
The previous prime is 411410114131. The next prime is 411410114149. The reversal of 411410114132 is 231411014114.
It can be written as a sum of positive squares in only one way, i.e., 404513808196 + 6896305936 = 636014^2 + 83044^2 .
It is a super-2 number, since 2×4114101141322 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 411410114098 and 411410114107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (411410114131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51426264263 + ... + 51426264270.
It is an arithmetic number, because the mean of its divisors is an integer number (119994616623).
Almost surely, 2411410114132 is an apocalyptic number.
It is an amenable number.
411410114132 is a deficient number, since it is larger than the sum of its proper divisors (308557585606).
411410114132 is a wasteful number, since it uses less digits than its factorization.
411410114132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 102852528537 (or 102852528535 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 411410114132 its reverse (231411014114), we get a palindrome (642821128246).
The spelling of 411410114132 in words is "four hundred eleven billion, four hundred ten million, one hundred fourteen thousand, one hundred thirty-two".
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