Base | Representation |
---|---|
bin | 111011110111100100101… |
… | …110100011101001001001 |
3 | 112120022021011200212101002 |
4 | 323313210232203221021 |
5 | 1014401210001042022 |
6 | 12430000125304345 |
7 | 603143520312551 |
oct | 73674456435111 |
9 | 15508234625332 |
10 | 4114121112137 |
11 | 1346875127283 |
12 | 565416a050b5 |
13 | 23ac6304021a |
14 | 1031a59a2161 |
15 | 7203ec9d092 |
hex | 3bde4ba3a49 |
4114121112137 has 2 divisors, whose sum is σ = 4114121112138. Its totient is φ = 4114121112136.
The previous prime is 4114121112107. The next prime is 4114121112259. The reversal of 4114121112137 is 7312111214114.
4114121112137 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3440045629696 + 674075482441 = 1854736^2 + 821021^2 .
It is a cyclic number.
It is not a de Polignac number, because 4114121112137 - 240 = 3014609484361 is a prime.
It is not a weakly prime, because it can be changed into another prime (4114121112107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057060556068 + 2057060556069.
It is an arithmetic number, because the mean of its divisors is an integer number (2057060556069).
Almost surely, 24114121112137 is an apocalyptic number.
It is an amenable number.
4114121112137 is a deficient number, since it is larger than the sum of its proper divisors (1).
4114121112137 is an equidigital number, since it uses as much as digits as its factorization.
4114121112137 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1344, while the sum is 29.
The spelling of 4114121112137 in words is "four trillion, one hundred fourteen billion, one hundred twenty-one million, one hundred twelve thousand, one hundred thirty-seven".
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