Base | Representation |
---|---|
bin | 1111010100111010… |
… | …0101100110111111 |
3 | 101121201200010222201 |
4 | 3311032211212333 |
5 | 31411221220413 |
6 | 1520130252331 |
7 | 203645323405 |
oct | 36516454677 |
9 | 11551603881 |
10 | 4114241983 |
11 | 1821422995 |
12 | 969a270a7 |
13 | 5074b0817 |
14 | 2b05b1475 |
15 | 1912de9dd |
hex | f53a59bf |
4114241983 has 4 divisors (see below), whose sum is σ = 4123167048. Its totient is φ = 4105316920.
The previous prime is 4114241941. The next prime is 4114241993. The reversal of 4114241983 is 3891424114.
4114241983 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3891424114 = 2 ⋅1945712057.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4114241983 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4114241933) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4461841 + ... + 4462762.
It is an arithmetic number, because the mean of its divisors is an integer number (1030791762).
Almost surely, 24114241983 is an apocalyptic number.
4114241983 is a deficient number, since it is larger than the sum of its proper divisors (8925065).
4114241983 is an equidigital number, since it uses as much as digits as its factorization.
4114241983 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8925064.
The product of its digits is 27648, while the sum is 37.
The square root of 4114241983 is about 64142.3571674755. The cubic root of 4114241983 is about 1602.3717407446.
The spelling of 4114241983 in words is "four billion, one hundred fourteen million, two hundred forty-one thousand, nine hundred eighty-three".
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