Base | Representation |
---|---|
bin | 10010101101011011101000… |
… | …10100000011101001000010 |
3 | 12101200021102021221010010012 |
4 | 21112231310110003221002 |
5 | 20343043232421040414 |
6 | 223301011543104522 |
7 | 11444341606305365 |
oct | 1126556424035102 |
9 | 171607367833105 |
10 | 41143443143234 |
11 | 12122922057623 |
12 | 4745a5ba42142 |
13 | 19c5a6b875543 |
14 | a234d354c0dc |
15 | 4b537e5d033e |
hex | 256b74503a42 |
41143443143234 has 4 divisors (see below), whose sum is σ = 61715164714854. Its totient is φ = 20571721571616.
The previous prime is 41143443143197. The next prime is 41143443143293. The reversal of 41143443143234 is 43234134434114.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 25773867779209 + 15369575364025 = 5076797^2 + 3920405^2 .
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 41143443143191 and 41143443143200.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10285860785807 + ... + 10285860785810.
Almost surely, 241143443143234 is an apocalyptic number.
41143443143234 is a deficient number, since it is larger than the sum of its proper divisors (20571721571620).
41143443143234 is a wasteful number, since it uses less digits than its factorization.
41143443143234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20571721571619.
The product of its digits is 663552, while the sum is 41.
Adding to 41143443143234 its reverse (43234134434114), we get a palindrome (84377577577348).
The spelling of 41143443143234 in words is "forty-one trillion, one hundred forty-three billion, four hundred forty-three million, one hundred forty-three thousand, two hundred thirty-four".
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