Base | Representation |
---|---|
bin | 100110010100011000… |
… | …110111000000100011 |
3 | 10221012102011110222001 |
4 | 212110120313000203 |
5 | 1133230412003103 |
6 | 30522412024431 |
7 | 2654410233544 |
oct | 462430670043 |
9 | 127172143861 |
10 | 41144250403 |
11 | 164a3947333 |
12 | 7b83162117 |
13 | 3b591575c9 |
14 | 1dc45484cb |
15 | 110c1ae01d |
hex | 994637023 |
41144250403 has 2 divisors, whose sum is σ = 41144250404. Its totient is φ = 41144250402.
The previous prime is 41144250353. The next prime is 41144250421. The reversal of 41144250403 is 30405244114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41144250403 - 213 = 41144242211 is a prime.
It is not a weakly prime, because it can be changed into another prime (41144250503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20572125201 + 20572125202.
It is an arithmetic number, because the mean of its divisors is an integer number (20572125202).
Almost surely, 241144250403 is an apocalyptic number.
41144250403 is a deficient number, since it is larger than the sum of its proper divisors (1).
41144250403 is an equidigital number, since it uses as much as digits as its factorization.
41144250403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 41144250403 its reverse (30405244114), we get a palindrome (71549494517).
The spelling of 41144250403 in words is "forty-one billion, one hundred forty-four million, two hundred fifty thousand, four hundred three".
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