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41145054113 is a prime number
BaseRepresentation
bin100110010100011011…
…111011001110100001
310221012110200022110002
4212110123323032201
51133231113212423
630522441145345
72654420121662
oct462433731641
9127173608402
1041145054113
11164a4346159
127b8348b255
133b59379387
141dc46b7369
15110c2bc228
hex9946fb3a1

41145054113 has 2 divisors, whose sum is σ = 41145054114. Its totient is φ = 41145054112.

The previous prime is 41145054107. The next prime is 41145054133. The reversal of 41145054113 is 31145054114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26995475809 + 14149578304 = 164303^2 + 118952^2 .

It is a cyclic number.

It is not a de Polignac number, because 41145054113 - 212 = 41145050017 is a prime.

It is not a weakly prime, because it can be changed into another prime (41145054133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20572527056 + 20572527057.

It is an arithmetic number, because the mean of its divisors is an integer number (20572527057).

Almost surely, 241145054113 is an apocalyptic number.

It is an amenable number.

41145054113 is a deficient number, since it is larger than the sum of its proper divisors (1).

41145054113 is an equidigital number, since it uses as much as digits as its factorization.

41145054113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 29.

Subtracting from 41145054113 its reverse (31145054114), we obtain a palindrome (9999999999).

The spelling of 41145054113 in words is "forty-one billion, one hundred forty-five million, fifty-four thousand, one hundred thirteen".