Base | Representation |
---|---|
bin | 1111010101000011… |
… | …0010100100001001 |
3 | 101121202202110222012 |
4 | 3311100302210021 |
5 | 31411343204322 |
6 | 1520150505305 |
7 | 203653246556 |
oct | 36520624411 |
9 | 11552673865 |
10 | 4114819337 |
11 | 1821787742 |
12 | 96a065235 |
13 | 507653555 |
14 | 2b06c1a2d |
15 | 1913a5ae2 |
hex | f5432909 |
4114819337 has 2 divisors, whose sum is σ = 4114819338. Its totient is φ = 4114819336.
The previous prime is 4114819333. The next prime is 4114819391. The reversal of 4114819337 is 7339184114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4113811321 + 1008016 = 64139^2 + 1004^2 .
It is a cyclic number.
It is not a de Polignac number, because 4114819337 - 22 = 4114819333 is a prime.
It is a super-2 number, since 2×41148193372 = 33863476352298239138, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4114819294 and 4114819303.
It is not a weakly prime, because it can be changed into another prime (4114819333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057409668 + 2057409669.
It is an arithmetic number, because the mean of its divisors is an integer number (2057409669).
Almost surely, 24114819337 is an apocalyptic number.
It is an amenable number.
4114819337 is a deficient number, since it is larger than the sum of its proper divisors (1).
4114819337 is an equidigital number, since it uses as much as digits as its factorization.
4114819337 is an evil number, because the sum of its binary digits is even.
The product of its digits is 72576, while the sum is 41.
The square root of 4114819337 is about 64146.8575769694. The cubic root of 4114819337 is about 1602.4466911621.
The spelling of 4114819337 in words is "four billion, one hundred fourteen million, eight hundred nineteen thousand, three hundred thirty-seven".
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