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411522225131 is a prime number
BaseRepresentation
bin1011111110100001010…
…00101101001111101011
31110100012200200001102202
411333100220231033223
523220244142201011
6513014541250415
741505622125053
oct5772050551753
91410180601382
10411522225131
11149586627706
1267909b63a0b
132ca637ccc34
1415cbc572563
15aa8824123b
hex5fd0a2d3eb

411522225131 has 2 divisors, whose sum is σ = 411522225132. Its totient is φ = 411522225130.

The previous prime is 411522225091. The next prime is 411522225143. The reversal of 411522225131 is 131522225114.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 411522225131 - 234 = 394342355947 is a prime.

It is a super-2 number, since 2×4115222251312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 411522225094 and 411522225103.

It is not a weakly prime, because it can be changed into another prime (411522225151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205761112565 + 205761112566.

It is an arithmetic number, because the mean of its divisors is an integer number (205761112566).

Almost surely, 2411522225131 is an apocalyptic number.

411522225131 is a deficient number, since it is larger than the sum of its proper divisors (1).

411522225131 is an equidigital number, since it uses as much as digits as its factorization.

411522225131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4800, while the sum is 29.

The spelling of 411522225131 in words is "four hundred eleven billion, five hundred twenty-two million, two hundred twenty-five thousand, one hundred thirty-one".