Base | Representation |
---|---|
bin | 111011111001011101111… |
… | …111001110100110001001 |
3 | 112120111111221210202212122 |
4 | 323321131333032212021 |
5 | 1014414341303304023 |
6 | 12430534042021025 |
7 | 603245112454103 |
oct | 73713577164611 |
9 | 15514457722778 |
10 | 4116155525513 |
11 | 1347719539149 |
12 | 5658a41a7775 |
13 | 23b1c8676315 |
14 | 103319c58573 |
15 | 7210d6ac2c8 |
hex | 3be5dfce989 |
4116155525513 has 2 divisors, whose sum is σ = 4116155525514. Its totient is φ = 4116155525512.
The previous prime is 4116155525507. The next prime is 4116155525549. The reversal of 4116155525513 is 3155255516114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2626613386489 + 1489542139024 = 1620683^2 + 1220468^2 .
It is a cyclic number.
It is not a de Polignac number, because 4116155525513 - 240 = 3016643897737 is a prime.
It is a super-2 number, since 2×41161555255132 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4116155525213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2058077762756 + 2058077762757.
It is an arithmetic number, because the mean of its divisors is an integer number (2058077762757).
Almost surely, 24116155525513 is an apocalyptic number.
It is an amenable number.
4116155525513 is a deficient number, since it is larger than the sum of its proper divisors (1).
4116155525513 is an equidigital number, since it uses as much as digits as its factorization.
4116155525513 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 450000, while the sum is 44.
The spelling of 4116155525513 in words is "four trillion, one hundred sixteen billion, one hundred fifty-five million, five hundred twenty-five thousand, five hundred thirteen".
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