4118026960643 has 2 divisors, whose sum is σ = 4118026960644. Its totient is φ = 4118026960642.

The previous prime is 4118026960637. The next prime is 4118026960661. The reversal of 4118026960643 is 3460696208114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4118026960643 - 2¹⁴ = 4118026944259 is a prime.

It is a super-3 number, since 3×4118026960643³ (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4118026960591 and 4118026960600.

It is not a weakly prime, because it can be changed into another prime (4118026960613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2059013480321 + 2059013480322.

It is an arithmetic number, because the mean of its divisors is an integer number (2059013480322).

Almost surely, 2^{4118026960643} is an apocalyptic number.

4118026960643 is a deficient number, since it is larger than the sum of its proper divisors (1).

4118026960643 is an equidigital number, since it uses as much as digits as its factorization.

4118026960643 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1492992, while the sum is 50.

The spelling of 4118026960643 in words is "four trillion, one hundred eighteen billion, twenty-six million, nine hundred sixty thousand, six hundred forty-three".