Base | Representation |
---|---|
bin | 10010101110110010111100… |
… | …11010011110000010111011 |
3 | 12101211202102020200202100220 |
4 | 21113121132122132002323 |
5 | 20344330234003201010 |
6 | 223334323312431123 |
7 | 11450621352155541 |
oct | 1127313632360273 |
9 | 171752366622326 |
10 | 41190320365755 |
11 | 12140798020740 |
12 | 4752b62b484a3 |
13 | 19ca2cc673832 |
14 | a2589d235d91 |
15 | 4b66c4c2c970 |
hex | 25765e69e0bb |
41190320365755 has 32 divisors (see below), whose sum is σ = 76124998499328. Its totient is φ = 18796295923200.
The previous prime is 41190320365739. The next prime is 41190320365783. The reversal of 41190320365755 is 55756302309114.
It is not a de Polignac number, because 41190320365755 - 24 = 41190320365739 is a prime.
It is a super-2 number, since 2×411903203657552 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a junction number, because it is equal to n+sod(n) for n = 41190320365698 and 41190320365707.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7342300291 + ... + 7342305900.
It is an arithmetic number, because the mean of its divisors is an integer number (2378906203104).
Almost surely, 241190320365755 is an apocalyptic number.
41190320365755 is a deficient number, since it is larger than the sum of its proper divisors (34934678133573).
41190320365755 is a wasteful number, since it uses less digits than its factorization.
41190320365755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14684606227.
The product of its (nonzero) digits is 3402000, while the sum is 51.
The spelling of 41190320365755 in words is "forty-one trillion, one hundred ninety billion, three hundred twenty million, three hundred sixty-five thousand, seven hundred fifty-five".
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