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4120443120004 = 221030110780001
BaseRepresentation
bin111011111101011101100…
…011000110100110000100
3112120220120202200010210121
4323331131203012212010
51020002131414320004
612432523324031324
7603456264431431
oct73753543064604
915526522603717
104120443120004
1113495197a3372
125666a0092544
1323b72ca41093
14103605472b88
15722aece0854
hex3bf5d8c6984

4120443120004 has 6 divisors (see below), whose sum is σ = 7210775460014. Its totient is φ = 2060221560000.

The previous prime is 4120443119963. The next prime is 4120443120019. The reversal of 4120443120004 is 4000213440214.

It can be written as a sum of positive squares in only one way, i.e., 3786324439104 + 334118680900 = 1945848^2 + 578030^2 .

It is a super-3 number, since 3×41204431200043 (a number of 39 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515055389997 + ... + 515055390004.

Almost surely, 24120443120004 is an apocalyptic number.

It is an amenable number.

4120443120004 is a deficient number, since it is larger than the sum of its proper divisors (3090332340010).

4120443120004 is a wasteful number, since it uses less digits than its factorization.

4120443120004 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1030110780005 (or 1030110780003 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 4120443120004 its reverse (4000213440214), we get a palindrome (8120656560218).

The spelling of 4120443120004 in words is "four trillion, one hundred twenty billion, four hundred forty-three million, one hundred twenty thousand, four".

Divisors: 1 2 4 1030110780001 2060221560002 4120443120004