Base | Representation |
---|---|
bin | 1011111111100000001… |
… | …10001010110100010101 |
3 | 1110101120110211221020121 |
4 | 11333300012022310111 |
5 | 23222334302322013 |
6 | 513143154231541 |
7 | 41524661366122 |
oct | 5776006126425 |
9 | 1411513757217 |
10 | 412050042133 |
11 | 149827563404 |
12 | 67a368855b1 |
13 | 2cb18c744a2 |
14 | 15d2c6c9749 |
15 | aab975158d |
hex | 5ff018ad15 |
412050042133 has 4 divisors (see below), whose sum is σ = 425341979008. Its totient is φ = 398758105260.
The previous prime is 412050042113. The next prime is 412050042179. The reversal of 412050042133 is 331240050214.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 412050042133 - 25 = 412050042101 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 412050042098 and 412050042107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (412050042113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6645968391 + ... + 6645968452.
It is an arithmetic number, because the mean of its divisors is an integer number (106335494752).
Almost surely, 2412050042133 is an apocalyptic number.
It is an amenable number.
412050042133 is a deficient number, since it is larger than the sum of its proper divisors (13291936875).
412050042133 is a wasteful number, since it uses less digits than its factorization.
412050042133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13291936874.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 412050042133 its reverse (331240050214), we get a palindrome (743290092347).
The spelling of 412050042133 in words is "four hundred twelve billion, fifty million, forty-two thousand, one hundred thirty-three".
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