Base | Representation |
---|---|
bin | 1011111111100000011… |
… | …11001011111101100001 |
3 | 1110101120122022001000102 |
4 | 11333300033023331201 |
5 | 23222340403443423 |
6 | 513143321032145 |
7 | 41525020443155 |
oct | 5776017137541 |
9 | 1411518261012 |
10 | 412052406113 |
11 | 149828928507 |
12 | 67a37625655 |
13 | 2cb195c14aa |
14 | 15d2cb43065 |
15 | aab9a6bc28 |
hex | 5ff03cbf61 |
412052406113 has 2 divisors, whose sum is σ = 412052406114. Its totient is φ = 412052406112.
The previous prime is 412052406013. The next prime is 412052406119. The reversal of 412052406113 is 311604250214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 398120617024 + 13931789089 = 630968^2 + 118033^2 .
It is a cyclic number.
It is not a de Polignac number, because 412052406113 - 214 = 412052389729 is a prime.
It is not a weakly prime, because it can be changed into another prime (412052406119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206026203056 + 206026203057.
It is an arithmetic number, because the mean of its divisors is an integer number (206026203057).
Almost surely, 2412052406113 is an apocalyptic number.
It is an amenable number.
412052406113 is a deficient number, since it is larger than the sum of its proper divisors (1).
412052406113 is an equidigital number, since it uses as much as digits as its factorization.
412052406113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 412052406113 its reverse (311604250214), we get a palindrome (723656656327).
The spelling of 412052406113 in words is "four hundred twelve billion, fifty-two million, four hundred six thousand, one hundred thirteen".
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