Base | Representation |
---|---|
bin | 101110110110011100011101… |
… | …1000101000100000100100101 |
3 | 2000001010200010211021012102012 |
4 | 1131230320323011010010211 |
5 | 413003344123411444331 |
6 | 4020245315125124005 |
7 | 152542316032661651 |
oct | 13554707305040445 |
9 | 2001120124235365 |
10 | 412103103234341 |
11 | 10a343a432a7482 |
12 | 3a278413559605 |
13 | 148c42046382bc |
14 | 73a9c7a483a61 |
15 | 3299b3292082b |
hex | 176ce3b144125 |
412103103234341 has 4 divisors (see below), whose sum is σ = 412127737305900. Its totient is φ = 412078469162784.
The previous prime is 412103103234281. The next prime is 412103103234353. The reversal of 412103103234341 is 143432301301214.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 126700800261025 + 285402302973316 = 11256145^2 + 16893854^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-412103103234341 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 412103103234298 and 412103103234307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (412103103234371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12317010686 + ... + 12317044143.
It is an arithmetic number, because the mean of its divisors is an integer number (103031934326475).
Almost surely, 2412103103234341 is an apocalyptic number.
It is an amenable number.
412103103234341 is a deficient number, since it is larger than the sum of its proper divisors (24634071559).
412103103234341 is a wasteful number, since it uses less digits than its factorization.
412103103234341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24634071558.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 412103103234341 its reverse (143432301301214), we get a palindrome (555535404535555).
The spelling of 412103103234341 in words is "four hundred twelve trillion, one hundred three billion, one hundred three million, two hundred thirty-four thousand, three hundred forty-one".
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