Base | Representation |
---|---|
bin | 1011111111100110100… |
… | …01111011010110000011 |
3 | 1110101201012100122110211 |
4 | 11333303101323112003 |
5 | 23222441441044011 |
6 | 513152343134551 |
7 | 41526210403063 |
oct | 5776321732603 |
9 | 1411635318424 |
10 | 412103456131 |
11 | 149854726104 |
12 | 67a50744457 |
13 | 2cb270567c3 |
14 | 15d358313a3 |
15 | aabe2a2b21 |
hex | 5ff347b583 |
412103456131 has 2 divisors, whose sum is σ = 412103456132. Its totient is φ = 412103456130.
The previous prime is 412103456101. The next prime is 412103456159. The reversal of 412103456131 is 131654301214.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 412103456131 - 27 = 412103456003 is a prime.
It is a super-2 number, since 2×4121034561312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 412103456093 and 412103456102.
It is not a weakly prime, because it can be changed into another prime (412103456101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206051728065 + 206051728066.
It is an arithmetic number, because the mean of its divisors is an integer number (206051728066).
Almost surely, 2412103456131 is an apocalyptic number.
412103456131 is a deficient number, since it is larger than the sum of its proper divisors (1).
412103456131 is an equidigital number, since it uses as much as digits as its factorization.
412103456131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 412103456131 its reverse (131654301214), we get a palindrome (543757757345).
The spelling of 412103456131 in words is "four hundred twelve billion, one hundred three million, four hundred fifty-six thousand, one hundred thirty-one".
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