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412104040034131 is a prime number
BaseRepresentation
bin101110110110011100111001…
…0111010101010111101010011
32000001010202120010000120010201
41131230321302322222331103
5413003403033222043011
64020245552112040031
7152542351166436454
oct13554716272527523
92001122503016121
10412104040034131
1110a344384083a85
123a278635233017
13148c43237479c3
1473a9d28a5d12b
153299b89cbacc1
hex176ce72eaaf53

412104040034131 has 2 divisors, whose sum is σ = 412104040034132. Its totient is φ = 412104040034130.

The previous prime is 412104040034111. The next prime is 412104040034173. The reversal of 412104040034131 is 131430040401214.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 412104040034131 - 221 = 412104037936979 is a prime.

It is a super-2 number, since 2×4121040400341312 (a number of 30 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 412104040034131.

It is not a weakly prime, because it can be changed into another prime (412104040034111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206052020017065 + 206052020017066.

It is an arithmetic number, because the mean of its divisors is an integer number (206052020017066).

Almost surely, 2412104040034131 is an apocalyptic number.

412104040034131 is a deficient number, since it is larger than the sum of its proper divisors (1).

412104040034131 is an equidigital number, since it uses as much as digits as its factorization.

412104040034131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 412104040034131 its reverse (131430040401214), we get a palindrome (543534080435345).

The spelling of 412104040034131 in words is "four hundred twelve trillion, one hundred four billion, forty million, thirty-four thousand, one hundred thirty-one".