Base | Representation |
---|---|
bin | 101110110110011100111001… |
… | …0111010101010111101010011 |
3 | 2000001010202120010000120010201 |
4 | 1131230321302322222331103 |
5 | 413003403033222043011 |
6 | 4020245552112040031 |
7 | 152542351166436454 |
oct | 13554716272527523 |
9 | 2001122503016121 |
10 | 412104040034131 |
11 | 10a344384083a85 |
12 | 3a278635233017 |
13 | 148c43237479c3 |
14 | 73a9d28a5d12b |
15 | 3299b89cbacc1 |
hex | 176ce72eaaf53 |
412104040034131 has 2 divisors, whose sum is σ = 412104040034132. Its totient is φ = 412104040034130.
The previous prime is 412104040034111. The next prime is 412104040034173. The reversal of 412104040034131 is 131430040401214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 412104040034131 - 221 = 412104037936979 is a prime.
It is a super-2 number, since 2×4121040400341312 (a number of 30 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 412104040034131.
It is not a weakly prime, because it can be changed into another prime (412104040034111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206052020017065 + 206052020017066.
It is an arithmetic number, because the mean of its divisors is an integer number (206052020017066).
Almost surely, 2412104040034131 is an apocalyptic number.
412104040034131 is a deficient number, since it is larger than the sum of its proper divisors (1).
412104040034131 is an equidigital number, since it uses as much as digits as its factorization.
412104040034131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 412104040034131 its reverse (131430040401214), we get a palindrome (543534080435345).
The spelling of 412104040034131 in words is "four hundred twelve trillion, one hundred four billion, forty million, thirty-four thousand, one hundred thirty-one".
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