412111403201335 has 4 divisors (see below), whose sum is σ = 494533683841608. Its totient is φ = 329689122561064.

The previous prime is 412111403201219. The next prime is 412111403201339. The reversal of 412111403201335 is 533102304111214.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 412111403201335 - 2⁹ = 412111403200823 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 412111403201297 and 412111403201306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (412111403201339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41211140320129 + ... + 41211140320138.

It is an arithmetic number, because the mean of its divisors is an integer number (123633420960402).

Almost surely, 2^{412111403201335} is an apocalyptic number.

412111403201335 is a deficient number, since it is larger than the sum of its proper divisors (82422280640273).

412111403201335 is an equidigital number, since it uses as much as digits as its factorization.

412111403201335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82422280640272.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 412111403201335 its reverse (533102304111214), we get a palindrome (945213707312549).

The spelling of 412111403201335 in words is "four hundred twelve trillion, one hundred eleven billion, four hundred three million, two hundred one thousand, three hundred thirty-five".