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4121130041297 is a prime number
BaseRepresentation
bin111011111110000110011…
…111011111111111010001
3112120222100122020100122222
4323332012133133333101
51020010033242310142
612433115423110425
7603512305241423
oct73760637377721
915528318210588
104121130041297
11134984151a515
12566852142415
1323b80c151499
1410366c7a4813
157230027cbd2
hex3bf867dffd1

4121130041297 has 2 divisors, whose sum is σ = 4121130041298. Its totient is φ = 4121130041296.

The previous prime is 4121130041291. The next prime is 4121130041321. The reversal of 4121130041297 is 7921400311214.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3568532571136 + 552597470161 = 1889056^2 + 743369^2 .

It is a cyclic number.

It is not a de Polignac number, because 4121130041297 - 26 = 4121130041233 is a prime.

It is a super-4 number, since 4×41211300412974 (a number of 52 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (4121130041291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060565020648 + 2060565020649.

It is an arithmetic number, because the mean of its divisors is an integer number (2060565020649).

Almost surely, 24121130041297 is an apocalyptic number.

It is an amenable number.

4121130041297 is a deficient number, since it is larger than the sum of its proper divisors (1).

4121130041297 is an equidigital number, since it uses as much as digits as its factorization.

4121130041297 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 35.

The spelling of 4121130041297 in words is "four trillion, one hundred twenty-one billion, one hundred thirty million, forty-one thousand, two hundred ninety-seven".