412120222021213 has 4 divisors (see below), whose sum is σ = 412120740068928. Its totient is φ = 412119703973500.

The previous prime is 412120222021139. The next prime is 412120222021217. The reversal of 412120222021213 is 312120222021214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-412120222021213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (412120222021217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 257828731 + ... + 259422232.

It is an arithmetic number, because the mean of its divisors is an integer number (103030185017232).

Almost surely, 2^{412120222021213} is an apocalyptic number.

It is an amenable number.

412120222021213 is a deficient number, since it is larger than the sum of its proper divisors (518047715).

412120222021213 is an equidigital number, since it uses as much as digits as its factorization.

412120222021213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 518047714.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 412120222021213 its reverse (312120222021214), we get a palindrome (724240444042427).

Subtracting from 412120222021213 its reverse (312120222021214), we obtain a palindrome (99999999999999).

The spelling of 412120222021213 in words is "four hundred twelve trillion, one hundred twenty billion, two hundred twenty-two million, twenty-one thousand, two hundred thirteen".