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41212220796833 is a prime number
BaseRepresentation
bin10010101111011011101111…
…10001111110111110100001
312101220211221112012220221212
421113231313301332332201
520400210112010444313
6223352344410555505
711452325151566042
oct1127556761767641
9171824845186855
1041212220796833
111214a00626a759
124757255438b95
1319cc3ac9a32a8
14a26979a988c9
154b705773e3a8
hex257b77c7efa1

41212220796833 has 2 divisors, whose sum is σ = 41212220796834. Its totient is φ = 41212220796832.

The previous prime is 41212220796793. The next prime is 41212220796853. The reversal of 41212220796833 is 33869702221214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22363138345024 + 18849082451809 = 4728968^2 + 4341553^2 .

It is a cyclic number.

It is not a de Polignac number, because 41212220796833 - 28 = 41212220796577 is a prime.

It is not a weakly prime, because it can be changed into another prime (41212220796853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20606110398416 + 20606110398417.

It is an arithmetic number, because the mean of its divisors is an integer number (20606110398417).

Almost surely, 241212220796833 is an apocalyptic number.

It is an amenable number.

41212220796833 is a deficient number, since it is larger than the sum of its proper divisors (1).

41212220796833 is an equidigital number, since it uses as much as digits as its factorization.

41212220796833 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1741824, while the sum is 50.

The spelling of 41212220796833 in words is "forty-one trillion, two hundred twelve billion, two hundred twenty million, seven hundred ninety-six thousand, eight hundred thirty-three".