Base | Representation |
---|---|
bin | 111011111110010111001… |
… | …101011010100111000111 |
3 | 112121000002011222210222211 |
4 | 323332113031122213013 |
5 | 1020011122042411401 |
6 | 12433203322404251 |
7 | 603522252226255 |
oct | 73762715324707 |
9 | 15530064883884 |
10 | 4121410513351 |
11 | 13499758762aa |
12 | 566910060687 |
13 | 23b8552a2991 |
14 | 103697b335d5 |
15 | 72319bd0951 |
hex | 3bf9735a9c7 |
4121410513351 has 4 divisors (see below), whose sum is σ = 4123119935304. Its totient is φ = 4119701091400.
The previous prime is 4121410513291. The next prime is 4121410513369. The reversal of 4121410513351 is 1533150141214.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4121410513351 - 213 = 4121410505159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4121410513391) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 854707360 + ... + 854712181.
It is an arithmetic number, because the mean of its divisors is an integer number (1030779983826).
Almost surely, 24121410513351 is an apocalyptic number.
4121410513351 is a deficient number, since it is larger than the sum of its proper divisors (1709421953).
4121410513351 is a wasteful number, since it uses less digits than its factorization.
4121410513351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1709421952.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 4121410513351 its reverse (1533150141214), we get a palindrome (5654560654565).
The spelling of 4121410513351 in words is "four trillion, one hundred twenty-one billion, four hundred ten million, five hundred thirteen thousand, three hundred fifty-one".
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