Base | Representation |
---|---|
bin | 10010101111011111010001… |
… | …11111011010110011010011 |
3 | 12101221000211220011202120022 |
4 | 21113233220333122303103 |
5 | 20400223004224102313 |
6 | 223353301100334055 |
7 | 11452423214016425 |
oct | 1127575077326323 |
9 | 171830756152508 |
10 | 41214120144083 |
11 | 1214a8a040a427 |
12 | 47576a554432b |
13 | 19cc6233389c3 |
14 | a26aba032815 |
15 | 4b711936dc08 |
hex | 257be8fdacd3 |
41214120144083 has 2 divisors, whose sum is σ = 41214120144084. Its totient is φ = 41214120144082.
The previous prime is 41214120144037. The next prime is 41214120144139. The reversal of 41214120144083 is 38044102141214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41214120144083 - 218 = 41214119881939 is a prime.
It is not a weakly prime, because it can be changed into another prime (41214120144683) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20607060072041 + 20607060072042.
It is an arithmetic number, because the mean of its divisors is an integer number (20607060072042).
Almost surely, 241214120144083 is an apocalyptic number.
41214120144083 is a deficient number, since it is larger than the sum of its proper divisors (1).
41214120144083 is an equidigital number, since it uses as much as digits as its factorization.
41214120144083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24576, while the sum is 35.
Adding to 41214120144083 its reverse (38044102141214), we get a palindrome (79258222285297).
The spelling of 41214120144083 in words is "forty-one trillion, two hundred fourteen billion, one hundred twenty million, one hundred forty-four thousand, eighty-three".
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