Base | Representation |
---|---|
bin | 111011111110011100001… |
… | …101111111010000110001 |
3 | 112121000022001010021222202 |
4 | 323332130031333100301 |
5 | 1020011310101041203 |
6 | 12433215523512545 |
7 | 603524322432623 |
oct | 73763415772061 |
9 | 15530261107882 |
10 | 4121494549553 |
11 | 1349a09253a07 |
12 | 566934228755 |
13 | 23b869817244 |
14 | 1036a4d6ac13 |
15 | 72322280388 |
hex | 3bf9c37f431 |
4121494549553 has 2 divisors, whose sum is σ = 4121494549554. Its totient is φ = 4121494549552.
The previous prime is 4121494549499. The next prime is 4121494549589. The reversal of 4121494549553 is 3559454941214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2166819328144 + 1954675221409 = 1472012^2 + 1398097^2 .
It is a cyclic number.
It is not a de Polignac number, because 4121494549553 - 26 = 4121494549489 is a prime.
It is not a weakly prime, because it can be changed into another prime (4121494548553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060747274776 + 2060747274777.
It is an arithmetic number, because the mean of its divisors is an integer number (2060747274777).
Almost surely, 24121494549553 is an apocalyptic number.
It is an amenable number.
4121494549553 is a deficient number, since it is larger than the sum of its proper divisors (1).
4121494549553 is an equidigital number, since it uses as much as digits as its factorization.
4121494549553 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15552000, while the sum is 56.
The spelling of 4121494549553 in words is "four trillion, one hundred twenty-one billion, four hundred ninety-four million, five hundred forty-nine thousand, five hundred fifty-three".
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