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4122011002132 = 221030502750533
BaseRepresentation
bin111011111110111011000…
…000000110010100010100
3112121001122000220210202001
4323332323000012110110
51020013334304032012
612433343053125044
7603543163262362
oct73767300062424
915531560823661
104122011002132
11134a153828421
12566a59189784
1323b91c80cb9a
141037137a6632
1572352798357
hex3bfbb006514

4122011002132 has 6 divisors (see below), whose sum is σ = 7213519253738. Its totient is φ = 2061005501064.

The previous prime is 4122011002117. The next prime is 4122011002189. The reversal of 4122011002132 is 2312001102214.

4122011002132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 2793330598276 + 1328680403856 = 1671326^2 + 1152684^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515251375263 + ... + 515251375270.

Almost surely, 24122011002132 is an apocalyptic number.

It is an amenable number.

4122011002132 is a deficient number, since it is larger than the sum of its proper divisors (3091508251606).

4122011002132 is a wasteful number, since it uses less digits than its factorization.

4122011002132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1030502750537 (or 1030502750535 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 4122011002132 its reverse (2312001102214), we get a palindrome (6434012104346).

The spelling of 4122011002132 in words is "four trillion, one hundred twenty-two billion, eleven million, two thousand, one hundred thirty-two".

Divisors: 1 2 4 1030502750533 2061005501066 4122011002132