Base | Representation |
---|---|
bin | 100110011001001001… |
… | …100010011100111011 |
3 | 10221101222110021121211 |
4 | 212121021202130323 |
5 | 1133411333320443 |
6 | 30534343543551 |
7 | 2656400145064 |
oct | 463111423473 |
9 | 127358407554 |
10 | 41224120123 |
11 | 16534a3966a |
12 | 7ba5a5abb7 |
13 | 3b6c8705b4 |
14 | 1dd0db956b |
15 | 11141d919d |
hex | 99926273b |
41224120123 has 2 divisors, whose sum is σ = 41224120124. Its totient is φ = 41224120122.
The previous prime is 41224120087. The next prime is 41224120139. The reversal of 41224120123 is 32102142214.
41224120123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41224120123 - 29 = 41224119611 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 41224120094 and 41224120103.
It is not a weakly prime, because it can be changed into another prime (41224127123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20612060061 + 20612060062.
It is an arithmetic number, because the mean of its divisors is an integer number (20612060062).
Almost surely, 241224120123 is an apocalyptic number.
41224120123 is a deficient number, since it is larger than the sum of its proper divisors (1).
41224120123 is an equidigital number, since it uses as much as digits as its factorization.
41224120123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 41224120123 its reverse (32102142214), we get a palindrome (73326262337).
The spelling of 41224120123 in words is "forty-one billion, two hundred twenty-four million, one hundred twenty thousand, one hundred twenty-three".
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