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41224120123 is a prime number
BaseRepresentation
bin100110011001001001…
…100010011100111011
310221101222110021121211
4212121021202130323
51133411333320443
630534343543551
72656400145064
oct463111423473
9127358407554
1041224120123
1116534a3966a
127ba5a5abb7
133b6c8705b4
141dd0db956b
1511141d919d
hex99926273b

41224120123 has 2 divisors, whose sum is σ = 41224120124. Its totient is φ = 41224120122.

The previous prime is 41224120087. The next prime is 41224120139. The reversal of 41224120123 is 32102142214.

41224120123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41224120123 - 29 = 41224119611 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41224120094 and 41224120103.

It is not a weakly prime, because it can be changed into another prime (41224127123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20612060061 + 20612060062.

It is an arithmetic number, because the mean of its divisors is an integer number (20612060062).

Almost surely, 241224120123 is an apocalyptic number.

41224120123 is a deficient number, since it is larger than the sum of its proper divisors (1).

41224120123 is an equidigital number, since it uses as much as digits as its factorization.

41224120123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 41224120123 its reverse (32102142214), we get a palindrome (73326262337).

The spelling of 41224120123 in words is "forty-one billion, two hundred twenty-four million, one hundred twenty thousand, one hundred twenty-three".