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412300023002040 = 2335371033312723737
BaseRepresentation
bin101110110111111000001010…
…0011010010111001110111000
32000001211111102111112212112210
41131233300110122113032320
5413020110421342031130
64020520003223135120
7152562456632251605
oct13557602432271670
92001744374485483
10412300023002040
1110a40a504388548
123a2aa60b5a44a0
1314909957760bc4
1473b55db4356ac
15329ed0a7535b0
hex176fc146973b8

412300023002040 has 256 divisors, whose sum is σ = 1286538687083520. Its totient is φ = 105616458731520.

The previous prime is 412300023002029. The next prime is 412300023002081. The reversal of 412300023002040 is 40200320003214.

It is a super-3 number, since 3×4123000230020403 (a number of 45 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 412300023001998 and 412300023002016.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 150011052 + ... + 152734788.

It is an arithmetic number, because the mean of its divisors is an integer number (5025541746420).

Almost surely, 2412300023002040 is an apocalyptic number.

412300023002040 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 412300023002040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (643269343541760).

412300023002040 is an abundant number, since it is smaller than the sum of its proper divisors (874238664081480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

412300023002040 is a wasteful number, since it uses less digits than its factorization.

412300023002040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2724222 (or 2724218 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 21.

Adding to 412300023002040 its reverse (40200320003214), we get a palindrome (452500343005254).

The spelling of 412300023002040 in words is "four hundred twelve trillion, three hundred billion, twenty-three million, two thousand, forty".